Let the above picture represent a spherical hourglass, where the bulbs are sections of spheres. Assume that the two bulbs have equal size. In order to calculate the volume of a spherical hourglass, double the volume of a single spherical bulb.
A cross section of a sphere can be describe by the equation x^2 + y^2 = r^2. Surprised? A sphere is a three-dimensional circular object.
By the diagram above, we calculate the volume of a spherical bulb giving radius r and height h. Using the Method of Discs with the discs rotating around the y-axis (x=0):
Top constraint: y = h
Bottom constraint: y = 0
Left constraint: x = 0
Right constraint: x = √(r^2 - y^2)
r(y) = √(r^2 - y^2)
And the volume of one of the spherical bulbs is:
∫ (r(y))^2 dy * π
∫ r^2 - y^2 dy * π
[ r^2 * y - y^3/3 ] * π
(r^2 * h - h^3/3) * π
. To get the volume of the spherical hourglass, double the volume of a spherical bulb:
V = 2 * π * (r^2 * h - h^3/3)
Note that if h = r, the bulbs are two half-spheres and that hourglass' volume:
V = 2 * π * (r^2 * r - r^3/3) = 2 * π * 2/3 * r^3 = 4/3 * π * r^3
Turns out to be the volume of a sphere.
Interesting how the mathematics checks out. With that I wish you a great day/night!
This blog is property of Edward Shore. 2014